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若lg2=0.3010,lg3=0.4771,求lg12的值

    发布时间:2019-07-07 11:09

    lg2 +lg5 =lg10 =1 因为lg2=0.3010 所以 lg5=0.699 因为lg根号45 =0.5 (lg5 + 2lg3) =0.5(0.699 +2 *0.4771) =0.8266 哪里看不懂 发消息给我。原式=lg45^(1/2) =(1/2)lg45 lg45=lg(3²×5) =lg3²+lg5 =2lg3+lg(10/2) =2lg3+lg10-lg2 =2lg3+1-lg2 所以原式=(2lg3+1-lg2)/2=0.8266lg2 +lg5 =lg10 =1 因为lg2=0.3010 所以 lg5=0.699 因为lg根号45 =0.5 (lg5 + 2lg3) =0.5(0.699 +2 *0.4771) =0.8266。lg3=0.4771,lg5 =lg(10/2) =lg10-lg2 =1-0.3010 =0.6989; lg12 =lg(4*3) =lg4+lg3 =lg2²+lg3= 2lg2+lg3 =2*0.3010+0.4771 =1.0791; log(1/2)90 =lg90/lg(1/2) [换底公式] =lg(3²*10)/lg(1/2) =(lg3²+lg10)/(lg1-lg2) =(2lg3+1)/(0-lg2) 。lgab=lga+lgb 6=2*3 lg6=lg2+lg3 lg12=lg3*4=lg3+lg4=lg3+lg2^2=lg3+2*lg2 lg√3=lg3^(1/2)=(lg3 )/2 根据同底对数计算性质 都可以用已知的对数来表示。lg12=lg3+lg4=lg3+2lg2=0.3010*2+0.4771=1.0791。直接代值求解即可。解:lg(3/2)=lg3-lg2=0.4771-0.3010=0.1761 因为lg4=lg2^2=2lg2=2x0.3010=0.6020 所以 lg2.4=lg12/5=lg12-lg5=lg3+lg4-lg10/2=lg3+lg4-(1-lg2)=0.4771+0.6020-1+0.3010=0.3801 lg√6=lg6^1/2=1/2lg6=1/2(lg2+lg3)=0.38905。我在线乐意解答。lg根号3 =1/2lg3 =1/2×0.4771 =0.23855 lg6=lg(2×3)=lg2+lg3=0.301+0.4771=0.7781 lg12=lg6+lg2=0.7781+0.301=1.0791。已知lg2=0.3010, lg75 =lg3+2lg5 =lg3+2-2lg2 =0.4771+2-3x0.3010 =1.5741。lg12=lg(2*2*3)=lg2+lg2+lg3=0.3010+0.3010+0.4771=1.0791; lg27/16=lg(3^3/2^4)=3lg3-4lg2=3*0.4471-4*0.3010=0.2273。
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